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If two zeroes of 2x4 - 3x3 - 3x2 +6x - 2 are root 2 and - root 2. Find its factors
Answers
Answer:
hint given
Step-by-step explanation:
P(x) = 2x4 - 3x3 - 3x2 +6x - 2
√2 is a zero then ( x - √2) is a factor of P(x)
- √2 is a zero then ( x + √2) is a factor P(x)
hence the product ( x - √2) ( x + √2) is also a factor of P (x)
I,e...( x^2 - 2) is also a factor of P (x)
now...P(x) ÷ ( x^2 - 2)
by division method...we get the quotient...
a quadratic polynomial Q(x)
then find the zeroes of Q(x)...which is ur answer
Answer:
hint given
Step-by-step explanation:
P(x) = 2x4 - 3x3 - 3x2 +6x - 2
√2 is a zero then ( x - √2) is a factor of P(x)
- √2 is a zero then ( x + √2) is a factor P(x)
hence the product ( x - √2) ( x + √2) is also a factor of P (x)
I,e...( x^2 - 2) is also a factor of P (x)
now...P(x) ÷ ( x^2 - 2)
by division method...we get the quotient...
a quadratic polynomial Q(x)
then find the zeroes of Q(x)...which is ur answer