beakar A contains sugar solution with 18% sugar. beaker B contains sugar solution with 12 % sugar. how much of each must he mixed together to get solution of 16% sugar weighing 240 gm of it.
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let the weight of 18% sugar be x
and that of 12% be y
x+y=240
and 18x+12y=16x240
solving for x and y we get x= 160 y=80
and that of 12% be y
x+y=240
and 18x+12y=16x240
solving for x and y we get x= 160 y=80
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