Question

Beaker A consists of sugar and water mixes in ratio 5:3 and beaker B has the same mixture in ratio 2:3. These 2 mixtures are mixed to form a new mixture containing half sugar and half water, they must be taken in ratio:

Answer 1

Given,

In first beaker,

Sugar:Water = 5:3

In second beaker,

Sugar:Water = 2:3

We know,

5+3 = 8

2+3 = 5

L.C.M = 8*5

= 40

L.C.M is the total quantity of mix

Quantity of mixture = 40 L

In vessel A,

M:W = 5:3

So, milk = 5/8*40

= 25 L

Water = 3/8*40

= 15 L

Similarly in vessel B,

Milk = 2/5*40

= 16 L

Water = 3/5*40

= 24 L

Now vessel C,

The ratio should be 1:1

Then,

Let the ratio of vessel A = x

Let the ratio of vessel B = y

In vessel C,

Measure of water = measure of milk

25x + 16y = 15x + 24y

10x = 8y

x/y = 4/5

So,

Vessel A:Vessel B = 4:5