Beakers a, b, c contain zinc sulphate silver nitrate and iron 2 sulphate solutions respectively CU is added to each beaker blue colour will appear in case of which beaker
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Answer : Beaker B
Beaker A = Zinc Sulphate
Beaker B = Silver nitrate
Beaker C = Iron ( II) Sulphate.
When Cu is added to each beaker, Blue color will appear in a beaker where Copper Sulphate or Nitrate is formed.
We know that, Reactivity order
K > Na > Ca > Mg > Al > Zn > Fe > Pb > [H] > Cu > Hg > Ag.
And, High reactive metal displaces a less reactive metal.
In Beaker A,
Zn is more reactive than Cu, So no reaction.
In Beaker B,
Cu is more reactive than Ag. So it displaces Ag from it's nitrate forming Copper nitrate.
In Beaker C,
Iron is more reactive than Cu, So no reaction.
Beaker A = Zinc Sulphate
Beaker B = Silver nitrate
Beaker C = Iron ( II) Sulphate.
When Cu is added to each beaker, Blue color will appear in a beaker where Copper Sulphate or Nitrate is formed.
We know that, Reactivity order
K > Na > Ca > Mg > Al > Zn > Fe > Pb > [H] > Cu > Hg > Ag.
And, High reactive metal displaces a less reactive metal.
In Beaker A,
Zn is more reactive than Cu, So no reaction.
In Beaker B,
Cu is more reactive than Ag. So it displaces Ag from it's nitrate forming Copper nitrate.
In Beaker C,
Iron is more reactive than Cu, So no reaction.
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In silver nitrate solution......According to the resistivity series Zn,Fe comes before Cu and Ag is lower in reactivity than Cu
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