bear a two- digit number in mind. without disclosing it, cunstruct a puzzle. create two algebraic relations between the two digits of the number and solve the puzzle
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I am a number, tell my identity, three times of me, add fifty. You still need forty to have a triple century
Let the number be x
3x+(50+40)=300
3x=300−90=210
x=3210
x=70
Hence, this is the answer.
Step-by-step explanation:
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