Question

bec
We see that prime factors 2 and 5 are not in pairs. Therefore 90 is not a perts
In order to get a perfect square, each factor of 90 must be paired. So we need
5 is their LCM. The LCM of 6.9 and 15 is 2x3x3 x 5 = 90.
rime factorisation of 90 is 90=2x3x3x5.
Tuare
ake pairs of 2 and 5. Therefore, 90 should be multiplied by 2 x 5, i.e., 10.
ence, the required square number is 90 x 10 = 900.
(iv) 65766601
EXERCISE 6.3
What could be the possible 'one's' digits of the square root of each of the follow,
numbers?
(1) 9801
(i) 99856
(iii) 998001
Without doing any calculation, find the numbers which are surely not perfect squar
(1) 153
(ii) 257
(ii) 408
(iv) 441
Find the square roots of 100 and 169 by the method of repeated subtraction.
Find the square roots of the following numbers by the Prime Factorisation Met
(i) 729
(ii) 400
(iii) 1764
(iv) 4090
(vi 7744
(vi) 9604
(vii) 5929
(viii) 921​

Answer 1

Answer:

hi bro why u not see what your teacher is explaining till what u will depend on this tell me bro

in exam brainly will not come to solve

so see what your teacher is explaining in school not on pocket size devices