becomes 72 kmh in 15 seconds. Fina
QS- A bus staring from rest accelerates in a straight line at a constant rate of 3
ms 2 for 3 seconds. Calculate the distance travelled by the bus during this time
interval.
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Answer:
here is your answer
given data :
initial velocity (u) = 0
acceleration (a) = 3 m/s²
time (t) = 8 seconds
to find : distance travelled
here we go
solution :
by using 2nd equation of motion
s = ut+1/2at²
s = 0+1/2*3*(8)²
s = 96 meter
hope it helps :)
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