been stuck on his question all day someone please help me
Answers
Step-by-step explanation:
Given :-
a) n²+3
b) 2n²
To find :-
For each sequence ,find the first 4 terms and 10th term ?
Solution :-
a)
Given general term = n²+3
Let an = n²+3 -----(1)
Put n = 1 in (1) then
a1 = (1)²+3
=> a1 = 1+3
=> a1 = 4
First term = 4
Put n = 2 in (1) then
a2 = (2)²+3
=> a2 = 4+3
=> a2 = 7
Second term = 7
Put n = 3 in (1) then
a1 = (3)²+3
=> a3= 9+3
=> a3= 12
Third term = 12
Put n = 4 in (1) then
a4 = (4)²+3
=> a4 = 16+3
=> a4= 19
Fourth term = 19
put n = 10 in (1) then
a10 = (10)²+3
=> a10 = 100+3
=> a10 = 103
10th term of the sequence = 103
b)
Given general term = 2n²
Let an = 2n² -----(1)
Put n = 1 in (1) then
a1 =2 (1)²
=> a1 = 2(1)
=> a1 = 2
First term = 2
Put n = 2 in (1) then
a2 =2 (2)²
=> a2 = 2(4)
=> a2 = 8
Second term = 2
Put n = 3 in (1) then
a3 =2 (3)²
=> a3 = 2(9)
=> a3 = 18
Third term = 18
Put n = 4 in (1) then
a4 =2 (4)²
=> a4 = 2(16)
=> a4 = 32
Fourth term = 32
put n = 10 in (1) then
a10 =2 (10)²
=> a10 = 2(100)
=> a10 = 200
10th term of the sequence = 200
Answer:-
a) The first four terms of n²+3 are 4,7,12,19
The 10th term of n²+3 is 103
b) The first four terms of 2n² are 2,8,18,32
The 10th term of 2n² is 200