Question

Beena’s present age is thrice of Meena’s age. If Meena’s age three years ago was x, then Beena’s
present age is:​

Answer 1

Let the common factor be x

Beena's age = 2x years

Meena's age = 3x years

After 2 years , ages of

Beena = 2x + 2

Meena = 3x + 2

given that ,

after two years, their sum will be 29 years,

So,

the following balanced equation will be formed

x = 5

So,

Beena's age = 2x = 2 × 5= 10 years

Meena's age = 3x = 3 × 5 = 15 years