Question

Before a chair manufacturer sells its beanbag chairs, they spot check a random sample of chairs on the production line. The table below shows the number of common problems found during one such spot check.
Common Problems
Frequency
Open seam
4
Cuts in upholstery
14
Understuffed
15
None
267
Total
300
If the manufacturer makes 1500 beanbag chairs per day, how many of those chairs would they expect to be understuffed?

Answer 1

Given : number of common problems found during one such spot check.

manufacturer makes 1500 beanbag chairs per day

To Find : how many of those chairs would they expect to be understuffed ?

Solution:

Common Problems   Frequency

Open seam                  4

Cuts in upholstery       14

Understuffed                15

None                             267

Total                              300

Probability of understuffed   = Understuffed   / Total

= 15/300

= 1/20

manufacturer makes 1500 beanbag chairs per day,

Number of  chairs  expected to be understuffed =  (1/20) x 1500

= 75

75   chairs  expected to be understuffed

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