Question

Before death a man left the following instructions for his fortune: half to his wife;1/7 of what was left to his son; 2/3 of what was left to his daughters; the man's dog got the remaining Rs 20000. How much money did the man leave behind altogether?​

Answer 1

Answer:

80000 you can see it for yourself easily

Step-by-step explanation:

easy

Answer 2

The man leave Rs.140000 behind altogether

Step-by-step explanation:

Let the total amount be x

He gave half of this amount to his wife

So, Wife's share = $\frac{x}{2}$

Remaining amount = $\frac{x}{2}$

1/7 of what was left to his son

Son's share = $\frac{1}{7}(\frac{x}{2})=\frac{x}{14}$

Remaining amount =$\frac{x}{2}-\frac{x}{14}=\frac{3x}{7}$

2/3 of what was left to his daughters

Daughter's share = $\frac{2}{3}(\frac{3x}{7})= \frac{2x}{7}$

Remaining amount = $\frac{3x}{7}-\frac{2x}{7}=\frac{x}{7}$

We are given that the man's dog got the remaining Rs 20000.

So, $20000=\frac{x}{7}\\140000=x$

Hence the man leave Rs.140000 behind altogether

#Learn more:

A man left one-third of his property to his daughter, one-fourth to his son, and the remaining Rs. 20000 to his wife. How much did the man leave/

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