beginning from rest, batman accelerates his batmobile to reach a velocity of 60 meters per second then he applies the break and the velocity of the batmobile decreases to 10 meters per second in the next 1 second. calculate the acceleration of the batmobile in both case
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u=0
v=12
t =60sec
a= v-u/t
a= 12-0/60
a=12/60
a= 1/5 = 0.2 m/s².
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