Question

Bela took a study loan of Rs. 100000 at 12% per annum compound half-yearly for year. how much did she pay at the end of the year

Answer 1

Step-by-step explanation:

principal =Rs 100000

rate = 10%/2=5%

time= 1×2 years =2 years

A=P(1+R/100) ^t

= Rs100000 (1+5/100)^2

=Rs100000(100+5/100)^2

= Rs100000 ×105/100 × 105/100

=Rs 110250

she has to pay Rs 110250 at the end of the year

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Amount=112360\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Principal(p) = 100000 \: rupees \\ \\ \tt: \implies Time(t) = 1 \: year \\ \\ \tt: \implies Rate\%(r) = 12\% \\ \\ \red{\underline \bold{To \: find :}} \\ \tt: \implies Amount(A) =?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies A = p(1 + \frac{ \frac{r}{2} }{100} )^{2t} \\ \\ \tt: \implies A= 100000 \times (1 + \frac{12}{2 \times 100} )^{2} \\ \\ \tt: \implies A =100000\times ( 1 + 0.06)^{2} \\ \\ \tt: \implies A=100000\times ( 1.06)^{2} \\ \\ \tt: \implies A = 100000\times 1.1236 \\ \\ \green{\tt: \implies A = 112360 \:rupees} \\ \\ \green{\tt \therefore Amount \:for \: \: loan \: is \: 112360\:rupees}$