Bell metal contains 80 per cent copper. The mass of ball metal which contains 1.5×10^20 atoms of copper
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let the mass of the metal ball be x gm
80℅ of x
= 1.5×10^20 atoms of copper
= 1.5×10^20/6.022×10^23 no. of moles
= (1.5/6.022×1000) moles
= 63.5 × 15/60220 gm of copper
= 9525/602200
= 381/24088
= 0.0158 gm
(80/100)x = 381/24088
x = 3810/192704
x = 0.0197 gm
80℅ of x
= 1.5×10^20 atoms of copper
= 1.5×10^20/6.022×10^23 no. of moles
= (1.5/6.022×1000) moles
= 63.5 × 15/60220 gm of copper
= 9525/602200
= 381/24088
= 0.0158 gm
(80/100)x = 381/24088
x = 3810/192704
x = 0.0197 gm
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