Bella bought a cot for ₹25000 and a sofa for ₹32000. If she sold the cot at a loss of 10% and the sofa at a profit of 10%, which of the following is the net profit or loss?
Answers
Answer:
- Net profit of Bella is ₹700.
Step-by-step explanation:
Given that:
- Bella bought a cot for ₹25000 and a sofa for ₹32000.
- She sold the cot at a loss of 10% and the sofa at a profit of 10%.
To Find:
- Net profit or loss.
Solution:
Finding SP of the cot:
As we know that:
Substituting the values,
Cutting off the zeros,
Multiplying the numbers,
Hence, Selling Price of the cot is ₹22500.
Finding SP of the sofa:
As we know that:
Substituting the values,
Cutting off the zeros,
Multiplying the numbers,
Hence, Selling Price of the sofa is ₹35200.
Now,
- Total CP = ₹(25000 + 32000) = ₹57000
- Total SP = ₹(22500 + 35200) = ₹57700
As,
- SP > CP
Therefore,
- It's a profit.
Finding total profit:
As we know that:
- Profit = SP - CP
Substituting the values,
Profit = SP - CP
= ₹(57700 - 57000)
= ₹700
Hence, total profit is ₹700.
Answer:
Net profit of Bella is ₹700.
Step-by-step explanation:
Given that:
Bella bought a cot for ₹25000 and a sofa for ₹32000.
She sold the cot at a loss of 10% and the sofa at a profit of 10%.
To Find:
Net profit or loss.
Solution:
Finding SP of the cot:
As we know that:
\sf{\circ\;SP=\dfrac{(100-loss\%)}{100}\times CP}∘SP=
100
(100−loss%)
×CP
Substituting the values,
\sf{\longmapsto\dfrac{(100-10)}{100}\times 25000}⟼
100
(100−10)
×25000
\sf{\longmapsto\dfrac{90}{100}\times 25000}⟼
100
90
×25000
Cutting off the zeros,
\sf{\longmapsto\dfrac{90}{1\!\!\!\not{0}\!\!\!\not{0}}\times 250\!\!\!\not{0}\!\!\!\not{0}}⟼
1
0
0
90
×250
0
0
\sf{\longmapsto90\times 250}⟼90×250
Multiplying the numbers,
\sf{\longmapsto22500}⟼22500
Hence, Selling Price of the cot is ₹22500.
Finding SP of the sofa:
As we know that:
\sf{\circ\;SP=\dfrac{(100+profit\%)}{100}\times CP}∘SP=
100
(100+profit%)
×CP
Substituting the values,
\sf{\longmapsto\dfrac{(100+10)}{100}\times 32000}⟼
100
(100+10)
×32000
\sf{\longmapsto\dfrac{110}{100}\times 32000}⟼
100
110
×32000
Cutting off the zeros,
\sf{\longmapsto\dfrac{110}{1\!\!\!\not{0}\!\!\!\not{0}}\times 320\!\!\!\not{0}\!\!\!\not{0}}⟼
1
0
0
110
×320
0
0
\sf{\longmapsto110\times 320}⟼110×320
Multiplying the numbers,
\sf{\longmapsto35200}⟼35200
Hence, Selling Price of the sofa is ₹35200.
Now,
Total CP = ₹(25000 + 32000) = ₹57000
Total SP = ₹(22500 + 35200) = ₹57700
As,
SP > CP
Therefore,
It's a profit.
Finding total profit:
As we know that:
Profit = SP - CP
Substituting the values,
Profit = SP - CP
= ₹(57700 - 57000)
= ₹700
Hence, total profit is 700
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