Question

BellaStark 1 please help me

Find the no of hydrogen atoms present in 11.2 litre of ammonia gas(NH3) at S.T.P​

Answer 1

Answer:

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Explanation:

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Answer 2

ANSWER :-

So,you can calculate no. Of moles by this formula

So,you can calculate no. Of moles by this formulaNo. Of moles = Given Volume ÷ 22.4

So,you can calculate no. Of moles by this formulaNo. Of moles = Given Volume ÷ 22.4But this formula is valid only for Gases at STP or NTP.

So,you can calculate no. Of moles by this formulaNo. Of moles = Given Volume ÷ 22.4But this formula is valid only for Gases at STP or NTP.SO,

So,you can calculate no. Of moles by this formulaNo. Of moles = Given Volume ÷ 22.4But this formula is valid only for Gases at STP or NTP.SO,no. Of moles = 11.2÷22.4 =0.5 moles

So,you can calculate no. Of moles by this formulaNo. Of moles = Given Volume ÷ 22.4But this formula is valid only for Gases at STP or NTP.SO,no. Of moles = 11.2÷22.4 =0.5 molesNo. Of molecules = 0.5 × Na (Remember its Avagadro's Number not Sodium :) )

So,you can calculate no. Of moles by this formulaNo. Of moles = Given Volume ÷ 22.4But this formula is valid only for Gases at STP or NTP.SO,no. Of moles = 11.2÷22.4 =0.5 molesNo. Of molecules = 0.5 × Na (Remember its Avagadro's Number not Sodium :) )No. Of atoms in 1 molecule of NH3 are 4

So,you can calculate no. Of moles by this formulaNo. Of moles = Given Volume ÷ 22.4But this formula is valid only for Gases at STP or NTP.SO,no. Of moles = 11.2÷22.4 =0.5 molesNo. Of molecules = 0.5 × Na (Remember its Avagadro's Number not Sodium :) )No. Of atoms in 1 molecule of NH3 are 4So, No. Of atoms will be

So,you can calculate no. Of moles by this formulaNo. Of moles = Given Volume ÷ 22.4But this formula is valid only for Gases at STP or NTP.SO,no. Of moles = 11.2÷22.4 =0.5 molesNo. Of molecules = 0.5 × Na (Remember its Avagadro's Number not Sodium :) )No. Of atoms in 1 molecule of NH3 are 4So, No. Of atoms will be0.5 × Na × 4

So,you can calculate no. Of moles by this formulaNo. Of moles = Given Volume ÷ 22.4But this formula is valid only for Gases at STP or NTP.SO,no. Of moles = 11.2÷22.4 =0.5 molesNo. Of molecules = 0.5 × Na (Remember its Avagadro's Number not Sodium :) )No. Of atoms in 1 molecule of NH3 are 4So, No. Of atoms will be0.5 × Na × 42Na

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