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It is know that 2 + a and 24 - b are divisible by 11. Prove that a + b is also divisible by 11.
Answers
➤ Answer
➤ Given
- 2 + a and 24 - b are divisible by 11.
➤ To Proof
- a + b is divisible by 11.
➤ Step By Step Explanation
- Step 1.
To watch the equations carefully.
- Step 2.
Let's assume that a and b are smallest number which can be added or subtracted to 2 and 24 respectively so that they can be divisible by 11.
[ Note - we are taking smallest values to make our calculations easy ]
➠ 2 + a = 11 ( which is divisible by 11 )
➠ a = 11 - 2 => a = 9
➠ 24 - b = 22 ( which is divisible by 11 )
➠ -b = 22 - 24 => b = 2
- Step 3.
Let's substitute the values of a and b and add them.
9 + 2 = 11
By adding a and b we conclude that the result is 11 which is divisible by 11.
➵ Hence proved.
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Solution!!
We can make our assumptions to solve this or we can try and do it using simple math. So, it is known that 2 + a and 24 - b are divisible by 11. We have to prove that a + b is also divisible by 11. We'll be getting more than one values of a and b while assuming. So, let's find out a suitable value of a and b whose sum is divisible by 11.
Make the two equations.
→ (2 + a) ÷ 11 = 1
→ (24 - b) ÷ 11 = 1
→ 2 + a = 11
→ 24 - b = 11
→ a = 11 - 2
→ 24 - 11 = b
→ a = 9
→ b = 13
Now,
→ a + b = 9 + 13 = 22
22 is divisible by 11 which means that a + b is also divisible by 11.
Hence, proved.