Math, asked by yahiyaman256, 2 months ago

(below figure).
semicircular portion with BC as diameter is cut off. Find the area of the remaining paper
A paper is in the form of a rectangle ABCD in which AB = 18cm and BC = 14cm.

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Answered by rohanshid35353

Answer:

below figure

symmetry or progression with busy as diameter is cut off find the area of the the remaining paper II II paper II is in the from all of the rectangle ABCD ine with ab =18 cm and we busy=14cm.

Answered by Anonymous

Answer:

A paper is in the form of a rectangle ABCD in which AB = 20 cm and BC = 14 cm. A semicircular portion with BC as diameter is cut off. Find the area of the remaining part

Area of the remaining part of sheet = Area of ABCD - Area of a semi-circle

= 20×14−21

× 7222

=280−77=203 cm

77=203 cm

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(below figure). semicircular portion with BC as diameter is cut off. Find the area of the remaining paper A paper is in the form of a rectangle ABCD in which AB = 18cm and BC = 14cm.