Math, asked by lilsunflower1020, 29 days ago

Below is a proof showing that the sum of a rational number and an irrational number is an irrational number.

Let a be a rational number and b be an irrational number.
Assume that a + b = x and that x is rational.
Then b = x – a = x + (–a).
x + (–a) is rational because _______________________.
However, it was stated that b is an irrational number. This is a contradiction.
Therefore, the assumption that x is rational in the equation a + b = x must be incorrect, and x should be an irrational number.
In conclusion, the sum of a rational number and an irrational number is irrational.

Answers

Answered by madhaviveny
0

Step-by-step explanation:

The sum of a rational and irrational number is always a rational number. The sum of a rational and irrational number is always an irrational number. Consider the conjecture that the sum of a rational number and an irrational number is ALWAYS irrational.

Answered by deepikaprashar43
1

Answer:

it's the ans.

Step-by-step explanation:

The sum of a rational and irrational number is always a rational number. The sum of a rational and irrational number is always an irrational number. Consider the conjecture that the sum of a rational number and an irrational number is ALWAYS irrational.19-Sep-2017

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