Ben Rushin is waiting at a stoplight. When it finally turns green, Ben accelerated from rest at a rate of a 6.00 m/s2 for a time of 4.10 seconds. Determine the displacement of Ben's car during this time period.
Answers
Answered by
9
s = ut + ½*at²
s = (0 * 4.10) + (½*6*4.10*4.10)
s = 0 + 50.43
s = 50.43 m
s = (0 * 4.10) + (½*6*4.10*4.10)
s = 0 + 50.43
s = 50.43 m
Answered by
4
Initial velocity (u) = 0
Displacement = ut + 0.5at²
= 0 + [0.5 × 6 m/s² × (4.10 s)²]
= 50.43 m
Displacement of Ben’s car is 50.43 m
Displacement = ut + 0.5at²
= 0 + [0.5 × 6 m/s² × (4.10 s)²]
= 50.43 m
Displacement of Ben’s car is 50.43 m
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