Math, asked by s23295asuhas00023, 6 months ago

Ben walks 500 meters from his house to the corner store. He then walks back toward his house but stops to talk to a neighbor when he is 200 meters from the corner store. If it takes Ben 910 seconds from the time he leaves his house until he stops to talk to his neighbor, what is his average velocity? (Round your answer to the nearest tenth of a meter per second.)
Ben’s average velocity is m/s.​

Answers

Answered by molly2001
3

I'm not good in physics

sry bro

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Answered by Anonymous
7

Step-by-step explanation:

Average velocity =

(displacement) / (time for the displacement)

and

(direction of the displacement) .

Displacement =

(distance from the start-point to the end-point)

and

(direction from the start-point to the end-point) .

When Ben is 200 meters from the corner store,

he is (500 - 200) = 300 meters from his house.

His displacement is

300 meters in the direction

from his house to the neighbor .

His average velocity is

(300/910) = 0.33 meters per second, in the

direction from his house to the neighbor .

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