Question

Ben walks 500 meters from his house to the corner store. He then walks back toward his house but stops to talk to a neighbor when he is 200 meters from the corner store. If it takes Ben 910 seconds from the time he leaves his house until he stops to talk to his neighbor, what is his average velocity? (Round your answer to the nearest tenth of a meter per second.)

I would like to know the answer in like 2 mins or less becuase i am in hurry. So could some please tell me the answer?

Answer 1

Ben's avg. Velocity = (500+200)/910 m/s = 0.769 m/s ≈0.8m/s