Question

Bending of cyclist on a leveled road. Explain through calculation!

Answer 1

hello dear friend ⭐⭐⭐⭐⭐⭐

For a body to move in a circular path, there has to be a centripetal force which is equal to the (velocity)^2/radius of circle, which keeps it in the circular path. ... when you bend, the direction of the normal force tilts, which results in a vertical as well as horizontal component of the force.

I hope it will help you ✨✨✨

Answer 2

Hello!

• R cosφ = $\sf mg$ --(i)

• R sinφ = $\dfrac{\sf mv^{2}}{\sf r}$ ---(ii)

Then,

$\dfrac{\sf Rsinφ}{\sf Rcosφ} = \dfrac{\sf \dfrac{\sf mv^{2}}{\sf r}}{\sf mg} \\ \\ \implies \sf tanφ = \dfrac{\sf v^{2}}{\sf rg}$

But,
$\sf tanφ= \sf \mu \:\:\: -(\sf Coefficient \:of\: friction)$

$\sf \mu = \dfrac{\sf v^{2}}{\sf rg} \\ \\ \implies \sf v = \boxed{\red{\bf{\sqrt{\sf \mu r g}}}} \:\: -(\sf Expression \:for \:max. \:speed)$

Cheers!