Question

Benzene and chloroform are mixed together . Mole fraction of benzene is 0.45 c alculate the percentage by wt. of benzene

Answer 1

Answer:

Let the mole fraction of benzene be X1 and toulene be X2

We know that in a solution X(1)+X(2)=1

As X(1)=0.1 and mole fraction of toulene will be 0.5

1 mole of benzene C6H6 = 78gm

so 0.5 mole of benzene  = 78×0.5=39gm

0.5 mole of toulene C6H5CH3=92×0.5=46gm

Weight % = Mass of component/total mass of the solution x100

Weight % of benzene = 3939+46×100=3985×100=45.88%                                                                                                                                                                      

Explanation: