benzene at certain temperature is 640 mm of HG a non-volatile solid weighing 2.1 75 grams is added to 39.0 8 of benzene the vapour pressure of solution is 600 mm of HG what is the molecular weight of solid substance
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mass of solid substance = 2.175g
mass of benzene = 39.08g
molar mass of benzene = 78g/mol
so, mole fraction of solute = n/(n + N)
where n is mole of solute and N is mole of solvent (benzene).
N = 39.08/78 = 0.5
from lowering of vapor pressure,
change in vapor pressure/vapor pressure of pure benzene = mole fraction of solute
or , (640 - 600)/640 = n/(n + 0.5)
or 40/640 = n/(n + 0.5)
or, n + 0.5 = 16n
or, n = 0.5/15 = 1/30
or , 2.175/M = 1/30, where M is molecular weight of solid substance.
or, M = 2.175 × 30 = 65.25 g/mol
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