Question

Benzene (C6H6) and toluene (C7H8) form nearly an ideal solution. At a certain temperature, the vapour pressure of pure benzene is
150 mm Hg and of pure toluene is 50 mm Hg. For this temperature, calculate the vapour pressure of solution containing 40 g
benzene and 40 g of toluene.
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Answer 1

Answer:

P total = Pa Xa + Pb Xb

No.of moles of benzene = 40 ÷ 78 = 0.51

No.of moles of toulene = 40 ÷ 92 = 0.43

Xa = 0.51 ÷ 0.94 = 0.542

Xb = 0.43 ÷ 0.94 = 0.458

P = 150 × 0.542 + 50 × 0.458

P = 81.3 + 22.9

P = 104 .2 atm

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