Benzene has three times as many two rupees coin as he has rs 5 coins if he has in all the sum of rupees 77 how many coins of each dominates does he have solution please
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Let the number of rs 5 coins be x.
according to the question ,Benzene has rs 2 coins of three times of no.of rs5 coins.i.e
= rs 2 = 3 × x = 3x
No .of rs 5 coins =5× x =5x
No.of rs 2 coins=3x × 2=6x
A.T.Q
= 5x + 6x = 77
=11x = 77
= x = 77÷11
= x = 7
hence, the total no.of rs 5 coins he has = 7
the total no.of rs 2 coins he has =3×7=21.
Hence,He has a total of amount rs 28 .(rs 21+rs7=rs28).
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