Question

ber. 111
As
34. In a zoo, the total number of rabbits and peacocks
50 and the total number of their legs is 140. Find
the number of rabbits and number of peacocks.​

Answer 1

Answer:

No. of rabbits is 20 and no of peacock is 30.

Step-by-step explanation:

(let rabbit = R and let peacock = P)

R+P=50...(1)

1R =4 legs

R rabbit = 4 R legs

1 peacock = 2 legs

P peacock = 2 P legs

therefore 4 R + 2 P = 140 ......(2)

multiply eq (1) to eq (2)

2( R +P) =50×2

2 R +2 P = 100 ....(3)

subtract eq (3) frm eq (2)

4R +2P - 2R - 2P = 140-100

2R = 40

no. of rabbits = 40/2 = 20

R +P = 50

P = 50-R

P = 50-20

P =30

no. of peacock = 30

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Answer 2

Answer:In a zoo, the total number of rabbits and peacocks

is 50 and the total number of their legs is 140. Find

the number of rabbits and number of peacocks.

Step-by-step explanation:

(let rabbit = R and let peacock = P)

R+P=50...(1)

1R =4 legs

R rabbit = 4 R legs

1 peacock = 2 legs

P peacock = 2 P legs

therefore 4 R + 2 P = 140 ......(2)

multiply eq (1) to eq (2)

2( R +P) =50×2

2 R +2 P = 100 ....(3)

subtract eq (3) frm eq (2)

4R +2P - 2R - 2P = 140-100

2R = 40

no. of rabbits = 40/2 = 20

R +P = 50

P = 50-R

P = 50-20

P =30

no. of peacock = 30

HOPE IT HELP U

PLS MARK ME AS BRAINLIEST