Berapa persentase (massa) nitrogen dalam ammonium Karbonat (NH₄)₂CO₃ ?
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Answered by
0
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Mass of (NH4)2CO3= 2(14+4)+12+48= 36+12+48=96amu.
Mass of N in (NH4)2CO3= 2(14)= 28 amu
% percentage of N in ammonium carbonate= 28/96*100= 29.16%
Mass of (NH4)2CO3= 2(14+4)+12+48= 36+12+48=96amu.
Mass of N in (NH4)2CO3= 2(14)= 28 amu
% percentage of N in ammonium carbonate= 28/96*100= 29.16%
Answered by
5
Ar N = 14
H = 1
C = 12
O = 16
Mr (NH4)2CO3 = 2×N + 8×H + C + 3×O = 28 + 8 + 12 + 48 = 96
%N = massa N/Mr × 100%
= 28/96 × 100% = 29.17%
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