Berrium chloride react with aluminium sulphate to give
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1) 3BaCl2 + Al2(SO4)3 = 2AlCl3 + 3BaSO4
2) This can be classified into 2 types: precepitation reaction and double displacement reaction
let me explain you as we have
3BaCl2 + Al2(SO4)3 produces 2AlCL3 +3BaSO4
because there are 2 aluminium and chloride so u make them into one and we also have 3 barrium and sulphate so u make them into another .....
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Answer:
Ba(so4)2+Alcl2
Explanation:
Bacl2 +2Also4----->Ba(so4)2 + 2Alcl
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