Chemistry, asked by Fcku, 7 months ago

Beryllium‑8 is a remarkable isotope because it is by far the smallest nucleus that can undergo an alpha decay.

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Answered by kingRohan5
3

Explanation:

Beryllium-8 has an extremely short half-life (8.19×10−17 seconds), and decays back into two helium-4 nuclei. ... Owing to the instability of 8Be, the triple-alpha process is the only reaction in which 12C and heavier elements may be produced in observed quantities.

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Answered by Anonymous
0

Answer:

Beryllium - 8 is a remarkable isotope because it is by far the smallest nucleus that can undergo an alpha decay .

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