Beryllium (Z = 4) has no unpaired electron in its ground state. However, in all its compounds beryllium
shows divalency. Explain.
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Beryllium is 4 th element so it's atomic number is 4 and it's electronic configuration is 1s2 2s2
Now beryllium has a vaccant p orbital so in the exited state this two electrons of 2 s orbital will be exited ok now that does not mean the both 2 electrons jump 1 between them jump to p orbital.
so now it has two unpaired electrons so it forms two bonds
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