Math, asked by sreyasthejuspeenikka, 1 month ago

best answer will be marked as brainliest​

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Answered by Athul4152
1

1.

 \frac{5}{x - 1}  +  \frac{1}{y - 2}  = 2 \\

\red{\implies} 5(y - 2) + x - 1 = 2

\red{\implies} 5y - 10 + x - 1 = 2

\red{\implies} x + 5y = 13 -  -  -  - (a)

 \rule{10cm}{0.05cm}

 \frac{6}{x - 1}   -  \frac{3}{y - 2}  = 1 \\

\red{\implies} 6(y - 2) - 3(x - 1) = 1

\red{\implies} 6y - 12 - 3x + 3 = 1

 - 3x + 6y = 10 -  -  -  -  - (b)

(a) \times 3\red{\implies} 3x + 15y = 39  -  -  - (c)

(b) + (c) \red{\implies} 21y = 49

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \red{\implies} y =  \frac{7}{3}  \\

x = 13 -  \frac{35}{3}  \\

x =  \frac{4}{3}  \\

 \rule{10cm}{0.05cm}

 \rule{10cm}{0.05cm}

2.

 \frac{1}{3x + y}  +  \frac{1}{3x - y}  =  \frac{3}{4}  \\

\red{\implies} 3x  - y + 3x  + y =  \frac{3}{4}  \\

\red{\implies} 6x =  \frac{3}{4}  \\

\red{\implies} x =  \frac{1}{8}  \\

 \rule{10cm}{0.05cm}

 \frac{1}{2(3x + y)}  -  \frac{1}{2(3x - y)}  =   \frac{ - 1}{8}  \\

\red{\implies} 6x   -  2y - 6x  - 2y =  \frac{ - 1}{8}  \\

\red{\implies}  - 4y =  \frac{ - 1}{8}  \\

\red{\implies} y =  \frac{1}{32}  \\

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