Question

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find value of y​

Answer 1

Step-by-step explanation:

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Answer 2

Taking out y common

We get y (b^2-a^2)=- -a^2b+b^3/a^2+b^2

Y=- -b (a^2+b^2)/a^2+b^2×b^2-a^2

Y=- -b/b^2-a^2