Question

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Answer 1

Answer:

only 1 integer which is 0

Solution

in log function only positive values are allowed

hence

x=(0, infinity)

but denominator can never me 0 so log should not be 0

hence

x-(0, infinity)-{1}

In root value should always be positive

hence

x=[-1,1]

But denominator can never be 0

hence

x=(-1,1) because putting 1 will make root 0

hence from both results it is clear that only one integer in domain is allowed which is $\huge 0$