#Best Question
@Sequence And Series
Let
![a_1,a_2,a_3,... a_1,a_2,a_3,...](https://tex.z-dn.net/?f=a_1%2Ca_2%2Ca_3%2C...)
be terms of an AP.
If
![\dfrac{a_1 +a_2 +a_3 + ... +a_p}{a_1 +a_2 +a_3 + ... +a_q} = \dfrac{ {p}^{2} }{ {q}^{2} } \\ \\ \sf and \\ \\ p \ne q \dfrac{a_1 +a_2 +a_3 + ... +a_p}{a_1 +a_2 +a_3 + ... +a_q} = \dfrac{ {p}^{2} }{ {q}^{2} } \\ \\ \sf and \\ \\ p \ne q](https://tex.z-dn.net/?f=++%5Cdfrac%7Ba_1+%2Ba_2+%2Ba_3+%2B+...+%2Ba_p%7D%7Ba_1+%2Ba_2+%2Ba_3+%2B+...+%2Ba_q%7D++%3D++%5Cdfrac%7B+%7Bp%7D%5E%7B2%7D+%7D%7B+%7Bq%7D%5E%7B2%7D+%7D+%5C%5C++%5C%5C++%5Csf+and+%5C%5C++%5C%5C+p+%5Cne+q)
then find
![\dfrac{a_6}{a_{21}} \dfrac{a_6}{a_{21}}](https://tex.z-dn.net/?f=+%5Cdfrac%7Ba_6%7D%7Ba_%7B21%7D%7D+)
Answers
Answered by
66
#Best Answer = 11/41
@Solution ☺
《♤ REFER TO THE ATTACHMENT ♤》
Attachments:
![](https://hi-static.z-dn.net/files/d3a/d0f339565dd69ad256e2dfdb73a0dc70.jpg)
Answered by
5
Answer:
11/41
Step-by-step explanation:
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