Question

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If one kg of fertilizer covers an area of half square metre, find the amount of fertilizer required to cover a circular field with radius 14 m.
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Answer 1

Answer:

Area = πr²

Area = π(14)² = 616 m²

Find the amount of fertiliser required:

1/2 m² = 1 kg

1m² = 1x2= 2 kg

616 m² = 2 x 616 = 1232 kg

Answer: 1232 kg of fertiliser is required

Answer 2

Answer:

Amount of fertilizer = 1232 kg

Step-by-step explanation:

Given:

• 1 kg of fertilizer covers ½ m²
• Radius of circular field = 14 m

To find:

Amount of fertilizer required to cover circular field = ?

Solution:

Firstly find out the area of circular field.

Area of circle = πr²

$\to \: \sf{Area \: of \: circle = \dfrac{22}{ \cancel{7}} \times \cancel{7} \times 2 \times 14}$

$\implies \sf{Area \: of \: circle = 22 \times 2 \times 14}$

$\implies \boldsymbol{Area \: of \: circle = 616 \: {m}^{2} }$

Now, 【½ m² → 1 kg】

So, 1 m² = 2 kg

Here,

We found out that area of circle = 616 m²

Hence amount of fertilizer = 2 × 616 = 1232 kg

∴ Amount of fertilizer = 1232 kg