Question

Between 1m nacl and 1m cacl2 which has higher freezing point

Answer 1

Answer:

it is quite simple as we know that the depression in freezing point is define as

∆Tf = Kf ×m ×i

Where i = vant off factor

∆Tf = Tf° - Tf

~ here in both case m=1

~Kf is constant

~but i =1 (for Nacl) and i =3 (for cacl2)

Hence the depression in freezing point is higher in cacl2.

if ∆Tf has higher value then Tf will be lesser in value and vice versa.

so, Tf is higher in Nacl