Math, asked by riya28071, 9 months ago

between 500 and 900.
33. Find the sum of all two-digit numbers
greater than 50 which when divided by 7
leaves remainder 4.​

Answers

Answered by garima34l
1

Answer:

the sum of all two digit numbers greater than 50 is 60 as when it will be divided with 7 it will remain it will leave the remainder 4

Answered by sohamnaik161812
1

Answer:

The number should be the form 7n+4

Should be 50<7n+4<100

∴ Numbers are 53,60,…..95

a=53

d=7

n

th

term =a+(n−1)d

⇒53+(n−1)7=95

⇒(n−1)

7=

42

6

⇒n=7

S

n

=

2

n

(2a+(n−1)d)

=

2

7

(2×53+(7−1)7)

=

2

7

[106+42]

=518.

Similar questions