Question

Between the plates of a parallel plate capacitor with a plate area of ​​30 cm2 and a capacitance of 40 pF
An object with a dielectric constant of 5.4 is placed. A potential difference of 50 volts is applied to the plates.
the amount of charge on the plates and the electric field between the plates.
Calculate.(ε0=8.85x10-12)

Answer 1

Answer:

electric field=47.080 vm

amount of charge=9.833 coulomb