Between the plates of a parallel plate capacitor with a plate area of 30 cm2 and a capacitance of 40 pF
An object with a dielectric constant of 5.4 is placed. A potential difference of 50 volts is applied to the plates.
the amount of charge on the plates and the electric field between the plates.
Calculate.(ε0=8.85x10-12)
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Answer:
electric field=47.080 vm
amount of charge=9.833 coulomb
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