Between two numbers whose sum is 13/6 an even number of arithmetic means is inserted ;the sum of these means exceeds their number by unity :how many means are there ?
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here is your answer
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➡let the numbers be A AND 13/6-A=(13-6A)/6
➡LET 2N MEANS BE INSERTED
➡SUM OF THE 2N+2 TERMS =(NUMBER OF TERMS/2)(FIRST TERM+LAST TERM)=
{(2N+2)/2}{13/6}=13(N+1)/6
➡SUM OF 2N MEANS = SUM OF 2N+2 TERMS - SUM OF FIRST & LAST TERMS
= 13(N+1)/6 - 13/6 = 13N/6
➡THIS IS MORE THAN THEIR NUMBER 2N BY 1 = 2N+1
➡13N/6 = 2N+1
➡13N=12N+6
➡N=6
✨✨✨✨✨✨✨✨✨✨✨✨✨
here is your answer
✨✨✨✨✨✨✨✨✨✨✨
➡let the numbers be A AND 13/6-A=(13-6A)/6
➡LET 2N MEANS BE INSERTED
➡SUM OF THE 2N+2 TERMS =(NUMBER OF TERMS/2)(FIRST TERM+LAST TERM)=
{(2N+2)/2}{13/6}=13(N+1)/6
➡SUM OF 2N MEANS = SUM OF 2N+2 TERMS - SUM OF FIRST & LAST TERMS
= 13(N+1)/6 - 13/6 = 13N/6
➡THIS IS MORE THAN THEIR NUMBER 2N BY 1 = 2N+1
➡13N/6 = 2N+1
➡13N=12N+6
➡N=6
✨✨✨✨✨✨✨✨✨✨✨✨✨
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