Math, asked by jeannvilladolid, 7 months ago

between what 2 integers the square root of the numbers can be found
1. 23
2. 113
3. 339
4. 640
5. 75

Answers

Answered by siddideshmukhe17
24

Answer:

1.4-5

2.10-11

3.18-19

4.25-26

5.8-9

Answered by subaphysics
0

Answer:

1. 4 and 5

2. 10 and 11

3.18 and 19

4.25 and26

5.8 and 9

Step-by-step explanation:

Step 1:

The square root of the given number is lies between two integer

let a and b be the integer.

c is the given number.

Step 2:

To find a^{2}\leq \sqrt[]{c} \leq b^{2}

1. 23

c=23

16\leq 23\leq 25

4^{2}\leq \sqrt[]{c} \leq 5^{2}

Therefore, 23 lies between the integer 4 and 5.

2. 113

c=133

100\leq 113\leq 121

10^{2}\leq \sqrt[]{113} \leq 11^{2}

Therefore, the square root of 113 lies between the integer 10 and 11.

3. 339

c=339

324\leq 339\leq 361

18^{2}\leq \sqrt[]{339} \leq 19^{2}

Therefore, the square root 339 lies between the integers 18 and 19.

4. 640

c=640

625\leq 640\leq 676

25^{2}\leq \sqrt[]{640} \leq 26^{2}

Therefore, the square root 640 lies between the integers 25 and 26.

5.75

c=75

64\leq 75\leq 91

25^{2}\leq \sqrt[]{640} \leq 26^{2}

Therefore, the square root 75 lies between the integers 8 and 9.

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