Question

Between what is the distance between point p 1, 2, 3 from xy plane

Answer 1

Answer:

the distance of the point p(4,-3,5) from xy plane = 5 unit

Step-by-step explanation:

to find the distance of the point p(4,-3,5) from xy plane

we will find minimum distance

at xy plane z = 0

for minimum distance point ( 4 , -3 , 0)

Minimum Distance = √(4-4)² + (-3-(-3))² + (0-5)² = 5 unit

To find exact distance co-ordinates of x & y will also required

I hope it will help you