Question

between which two consecutive integers
$\sqrt{120}$
does the square root lie

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Answer 1

Answer:

Nahi pata............

Answer 2

Step-by-step explanation:

Given Between which two consecutive integers  does the square root lie

• We need to find between which two consecutive integers √120 lie….
• So we get 1^2 = 1
•                2^2 = 4
•                3^2 = 9
•                4^2 = 16
•               5^2 = 25
•               6^2 = 36
•                7^2 = 49
•               ………..
•                ………..
•                …………
•                10^2 = 100  So 100 < 120
•                11^2 = 121 So 120 < 121
• Therefore we have 100 < 120 < 121
•                       So √100 < √120 < √121
•                              10 < √120 < 11
• So the number lies between 10 and 11

Reference link will be

https://brainly.in/question/27212330