beuebbdbdn nshsjbssb
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given Z (Be) = 4
N = nth excited state + 1 = 3+ 1 =4
(velocity )n = 2.188 × 10^6 × Z/ N metre / sec
ON substituting values of Z and N
Velocity = 2.188× 10^6 × 4/4
= 2.188 ×10^6 m/sec
= 2.188 × 10^3 km/sec
N = nth excited state + 1 = 3+ 1 =4
(velocity )n = 2.188 × 10^6 × Z/ N metre / sec
ON substituting values of Z and N
Velocity = 2.188× 10^6 × 4/4
= 2.188 ×10^6 m/sec
= 2.188 × 10^3 km/sec
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