BH is perpendicular to AC. Find x the length of BC.
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Answered by
24
Answer-:
AC= 19
Then CH= 19/2= 9.5
Given BH= 11
Then find the BC
BC= √(9.5)^2+ (11)^2
=> √90.25 +121
=> √211.5
=> 14.54..
AC= 19
Then CH= 19/2= 9.5
Given BH= 11
Then find the BC
BC= √(9.5)^2+ (11)^2
=> √90.25 +121
=> √211.5
=> 14.54..
hui
sis plz reply
CH = 9.5 how?
alright but its not mentioned in the ques that HA = HC
hi soma
Answered by
7
AC=19
BH=11
In triangle BHC
by Pythagoras theorem
xsq.=11sq.+19/2sq.
xsq.=121+361/4
x sq.= 484/4+361/4
x sq.= 845/4
x =underroot 845/4
x=
BH=11
In triangle BHC
by Pythagoras theorem
xsq.=11sq.+19/2sq.
xsq.=121+361/4
x sq.= 484/4+361/4
x sq.= 845/4
x =underroot 845/4
x=
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