Math, asked by sd4939522, 2 months ago




*बहुपद, "2x² – x – 6" के शून्यकों को ज्ञात कीजिए।*

1️⃣ 2 और –3/2
2️⃣ –2 और 2/3
3️⃣ –2 और 3/2
4️⃣ 2 और –2/3​

Answers

Answered by Anonymous
2

Answer:

2x {}^{2}  - x - 6 = 0 \\ 2x {}^{2} - 4x + 3x - 6 = 0 \\

2x(x-2) +3(x-2) =0

(x-2) (2x+3) =0

x=2, x=-3/2 option 1 is correct

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