Question

*बहुपद, "2x² – x – 6" के शून्यकों को ज्ञात कीजिए।*

Answer 1

Answer:

Explanation:

Let, 2x²-x-6 =0

2x²-4x+3x-6=0

2x(x-2) + 3(x-2) = 0

(2x+3)(x-2 )= 0

x-2 = 0/(2x+3)

x-2 = 0

x = 2

(2x+3)(x-2 )= 0

2x+3 = 0/(x-2)

2x+3 = 0

2x = -3

x = -3/2

∴ बहुपद, "2x² – x – 6 के शून्यकों  x = -3/2 , 2 हैं