Math, asked by paridiwakar98, 7 months ago

बहुपद 4y2+ 8y-5 के गुणनखंड कीजिए​

Answers

Answered by Biswasreema04
1

Answer:

 {4y}^{2}  + 8y - 5

 =  {4y}^{2}  + 10y - 2y - 5

 = 2y(2y + 5) - 1(2y + 5)

 = (2 y+ 5)(2 y- 1)

Answered by Anujmiskin
1

Answer:

4y2+8y-5

4y2+10y-2y-5

2y(2y+5)-1(2y+5)

(2y-1) (2y+5)

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