Math, asked by dagwarpoonamchand8, 3 days ago

बहुपद 6x^ 2 +13x+7 के शुन्यकों योगफल होगा।​

Answers

Answered by vijiraja0304
0

Answer:

6x^2+6x+7x+7=0 (separate 13x as 6x+7x)

6x(x+1) +7(x+1) =0 (common out the similar terms]

(x+1)[6x+7] =0

x+1=0 ; 6x+7 =0

so, x=-1 ; x=-7/6

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